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bounded geometric morphism in nLab

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Idea

Given a geometric morphism f:ℰ⟶𝒮f \colon \mathcal{E} \longrightarrow \mathcal{S}, we may regard ℰ\mathcal{E} as a topos over 𝒮\mathcal{S} via ff. The geometric morphism ff being bounded is the “over 𝒮\mathcal{S}” version of ℰ\mathcal{E} being a Grothendieck topos.

Definition

Definition

A geometric morphism f=(f *⊣f *):ℰ⟶𝒮f = (f^*\dashv f_*) \colon \mathcal{E} \longrightarrow \mathcal{S} between toposes is called bounded, if any of the following three equivalent condition holds.

  • There exists an object B∈ℰB \in \mathcal{E} – called a bound of ff – such that every A∈ℰA \in \mathcal{E} is a subquotient of an object of the form (f *I)×B(f^* I) \times B for some I∈𝒮I \in \mathcal{S}: this means that there exists a diagram

    S →epi A mono↓ (f *I)×B. \array{ S &\xrightarrow{\; epi \;}& A \\ {}^{\mathllap{mono}} \big\downarrow \\ (f^* I) \times B } \,.

  • The gluing fibration? (ℰ/f *)→𝒮(\mathcal{E}/f^*)\to \mathcal{S} has a fibered separating family.

  • There exists a B∈ℰB\in\mathcal{E} such that for every A∈ℰA\in\mathcal{E} the composite

    f *f *(A˜ B)×B→A˜ B×B→A˜ f^*f_*(\tilde A^B) \times B \to \tilde A^B\times B\to \tilde A

    is an epimorphism, where A˜\tilde A is the partial map classifier of AA.

Proof of the equivalence.

Lemma B3.1.6 in the Elephant

If we regard ℰ\mathcal{E} as a topos over 𝒮\mathcal{S} via ff, then when ff is bounded we call ℰ\mathcal{E} a bounded 𝒮\mathcal{S}-topos.

Properties

As relative Grothendieck toposes

If f≔Γ:ℰ→Setf \coloneqq \Gamma\colon \mathcal{E}\to Set is the global section geometric morphism of a topos (such a geometric morphism being unique if it exists), then it is bounded if and only if ℰ\mathcal{E} is a Grothendieck topos. As such we can also call Grothendieck toposes “bounded Set-toposes”.

More generally, bounded toposes over 𝒮\mathcal{S} are precisely the toposes of 𝒮\mathcal{S}-valued internal sheaves on internal sites in 𝒮\mathcal{S} (Johnstone, Section B3.3).

If f:ℰ→𝒮f \colon \mathcal{E}\to\mathcal{S} is bounded and 𝒮\mathcal{S} is a Grothendieck topos, then ℰ\mathcal{E} is a Grothendieck topos as well. This is a consequence of prop. .

Stability under composition

Proposition

Bounded geometric morphisms are stable under composition.

Proof

Assume that f:ℱ→𝒮f : \mathcal{F} \to \mathcal{S} is bounded by B∈ℱB\in\mathcal{F}, and g:𝒢→ℱg:\mathcal{G}\to\mathcal{F} is bounded by C∈𝒢C\in\mathcal{G}. Let A∈𝒢A\in\mathcal{G}. Then there exist J∈ℱJ\in \mathcal{F} and I∈𝒮I\in\mathcal{S}, and subquotient spans g *J×C←•→Ag^*J\times C\leftarrow\bullet\rightarrow A and f *I×B←•→Jf^*I\times B\leftarrow\bullet\rightarrow J. By applying g *(−)×Cg^*(-)\times C to the second subquotient and forming a pullback, we get the diagram

• → • →A ↓ ↓ • → g*J×C ↓ g *f *I×g *B×C \begin{matrix} \bullet & \to & \bullet & \to A \\ \downarrow && \downarrow \\ \bullet & \rightarrow & g*J\times C \\ \downarrow \\ g^*f^* I\times g^* B \times C \end{matrix}

where the vertical arrows are monos and the horizontal ones are epis (using the fact that epis are stable under g *g^*, products, and pullbacks), from which we can see that fgf g is bounded by g *B×Cg^*B\times C.

Almost all geometric morphisms in practice are bounded, so that often when people work in the 2-category Topos of toposes and geometric morphisms, they mean that the geometric morphisms are bounded. See unbounded topos for the few examples of unbounded geometric morphisms.

References

definition B3.1.7 in

Last revised on February 12, 2024 at 14:13:30. See the history of this page for a list of all contributions to it.