reduced homology in nLab
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In general, the homology of a point is not trivial but is concentrated in degree 0 on the given coefficient object. For some applications, though, it is convenient to divide out that contribution such as to have the homology of the point be entirely trivial. This is called reduced homology.
Definition
Reduced singular homology
We discuss the reduced version of singular homology.
Let XX be a topological space. Write C •(X)C_\bullet(X) for its singular chain complex.
Definition
The augmentation map is the homomorphism of abelian groups
ϵ:C 0(X)→ℤ \epsilon \colon C_0(X) \to \mathbb{Z}
which adds up all the coefficients of all 0-chains:
ϵ::∑ in iσ i↦∑ in i. \epsilon \colon \colon \sum_{i} n_i \sigma_i \mapsto \sum_i n_i \,.
Since the boundary of a 1-chain is in the kernel of this map, it constitutes a chain map
ϵ:C •(X)→ℤ, \epsilon \colon C_\bullet(X) \to \mathbb{Z} \,,
where now ℤ\mathbb{Z} is regarded as a chain complex concentrated in degree 0.
Definition
The reduced singular chain complex C˜ •(X)\tilde C_\bullet(X) of XX is the kernel of the augmentation map, the chain complex sitting in the short exact sequence
0→C˜ •(X)→C •(X)→ϵℤ→0. 0 \to \tilde C_\bullet(X) \to C_\bullet(X) \stackrel{\epsilon}{\to} \mathbb{Z} \to 0 \,.
The reduced singular homology H˜ •(X)\tilde H_\bullet(X) of XX is the chain homology of the reduced singular chain complex
H˜ •(X)≔H •(C˜ •(X)). \tilde H_\bullet(X) \coloneqq H_\bullet(\tilde C_\bullet(X)) \,.
Equivalently:
Definition
The reduced singular homology of XX, denoted H˜ •(X)\tilde H_\bullet(X), is the chain homology of the augmented chain complex
⋯→C 2(X)→∂ 2C 1(X)→∂ 1C 0(X)→ϵℤ→0. \cdots \to C_2(X) \stackrel{\partial_2}{\to} C_1(X) \stackrel{\partial_1}{\to} C_0(X) \stackrel{\epsilon}{\to} \mathbb{Z} \to 0 \,.
Properties
Relation to ordinary homology
Let XX be a topological space, H •(X)H_\bullet(X) its singular homology and H˜ •(X)\tilde H_\bullet(X) its reduced singular homology, def. .
Proposition
For n∈ℕn \in \mathbb{N} there is an isomorphism
H n(X)≃{H˜ n(X) forn≥1 H˜ 0(X)⊕ℤ forn=0 H_n(X) \simeq \left\{ \array{ \tilde H_n(X) & for \; n \geq 1 \\ \tilde H_0(X) \oplus \mathbb{Z} & for\; n = 0 } \right.
Proof
The homology long exact sequence of the defining short exact sequence C˜ •(C)→C •(X)→ϵℤ\tilde C_\bullet(C) \to C_\bullet(X) \stackrel{\epsilon}{\to} \mathbb{Z} is, since ℤ\mathbb{Z} here is concentrated in degree 0, of the form
⋯→H˜ n(X)→H n(X)→0→⋯→0→⋯→H˜ 1(X)→H 1(X)→0→H˜ 0(X)→H 0(X)→ϵℤ→0. \cdots \to \tilde H_n(X) \to H_n(X) \to 0 \to \cdots \to 0 \to \cdots \to \tilde H_1(X) \to H_1(X) \to 0 \to \tilde H_0(X) \to H_0(X) \stackrel{\epsilon}{\to} \mathbb{Z} \to 0 \,.
Here exactness says that all the morphisms H˜ n(X)→H n(X)\tilde H_n(X) \to H_n(X) for positive nn are isomorphisms. Moreover, since ℤ\mathbb{Z} is a free abelian group, hence a projective object, the remaining short exact sequence
0→H˜ 0(X)→H 0(X)→ℤ→0 0 \to \tilde H_0(X) \to H_0(X) \to \mathbb{Z} \to 0
is split (as discussed there) and hence H 0(X)≃H˜ 0(X)⊕ℤH_0(X) \simeq \tilde H_0(X) \oplus \mathbb{Z}.
Proposition
For X=*X = * the point, the morphism
H 0(ϵ):H 0(X)→ℤ H_0(\epsilon) \colon H_0(X) \to \mathbb{Z}
is an isomorphism. Accordingly the reduced homology of the point vanishes in every degree:
H˜ •(*)≃0. \tilde H_\bullet(*) \simeq 0 \,.
Proof
By the discussion at Singular homology – Relation to homotopy groups we have that
H n(*)≃{ℤ forn=0 0 otherwise. H_n(*) \simeq \left\{ \array{ \mathbb{Z} & for \; n = 0 \\ 0 & otherwise } \right. \,.
Moreover, it is clear that ϵ:C 0(*)→ℤ\epsilon \colon C_0(*) \to \mathbb{Z} is the identity map.
Relation to relative homology
Proof
Consider the sequence of topological subspace inclusions
∅↪*↪xX. \emptyset \hookrightarrow * \stackrel{x}{\hookrightarrow} X \,.
By the discussion at Relative homology - long exact sequences this induces a long exact sequence of the form
⋯→H n+1(*)→H n+1(X)→H n+1(X,*)→H n(*)→H n(X)→H n(X,*)→⋯→H 1(X)→H 1(X,*)→H 0(*)→H 0(x)H 0(X)→H 0(X,*)→0. \cdots \to H_{n+1}(*) \to H_{n+1}(X) \to H_{n+1}(X,*) \to H_n(*) \to H_n(X) \to H_n(X,*) \to \cdots \to H_1(X) \to H_1(X,*) \to H_0(*) \stackrel{H_0(x)}{\to} H_0(X) \to H_0(X,*) \to 0 \,.
Here in positive degrees we have H n(*)≃0H_n(*) \simeq 0 and therefore exactness gives isomorphisms
H n(X)→≃H n(X,*)∀ n≥1 H_n(X) \stackrel{\simeq}{\to} H_n(X,*)\;\; \forall_{n \geq 1}
and hence with prop. isomorphisms
H˜ n(X)→≃H n(X,*)∀ n≥1. \tilde H_n(X) \stackrel{\simeq}{\to} H_n(X,*)\;\; \forall_{n \geq 1} \,.
It remains to deal with the case in degree 0. To that end, observe that H 0(x):H 0(*)→H 0(X)H_0(x) \colon H_0(*) \to H_0(X) is a monomorphism: for this notice that we have a commuting diagram
H 0(*) →id H 0(*) H 0(x)↓ H 0(f)↗ ↓ ≃ H 0(ϵ) H 0(X) →H 0(ϵ) ℤ, \array{ H_0(*) &\stackrel{id}{\to}& H_0(*) \\ {}^{\mathllap{H_0(x)}}\downarrow &{}^{\mathllap{H_0(f)}}\nearrow& \downarrow^{\mathrlap{H_0(\epsilon)}}_\simeq \\ H_0(X) &\stackrel{H_0(\epsilon)}{\to}& \mathbb{Z} } \,,
where f:X→*f \colon X \to * is the terminal map. That the outer square commutes means that H 0(ϵ)∘H 0(x)=H 0(ϵ)H_0(\epsilon) \circ H_0(x) = H_0(\epsilon) and hence the composite on the left is an isomorphism. This implies that H 0(x)H_0(x) is an injection.
Therefore we have a short exact sequence as shown in the top of this diagram
0 → H 0(*) ↪H 0(x) H 0(X) → H 0(X,*) → 0 ≃↘ ↓ H 0(ϵ) ℤ. \array{ 0 &\to& H_0(*) &\stackrel{H_0(x)}{\hookrightarrow}& H_0(X) &\stackrel{}{\to}& H_0(X,*) &\to& 0 \\ && & {}_{\mathllap{\simeq}}\searrow & \downarrow^{\mathrlap{H_0(\epsilon)}} & \\ && && \mathbb{Z} } \,.
Using this we finally compute
H˜ 0(X) ≔kerH 0(ϵ) ≃coker(H 0(x)) ≃H 0(X,*). \begin{aligned} \tilde H_0(X) & \coloneqq ker H_0(\epsilon) \\ & \simeq coker( H_0(x) ) \\ & \simeq H_0(X,*) \end{aligned} \,.
Relation to wedge sums
Let {*→X i} i\{* \to X_i\}_i be a set of pointed topological spaces. Write ∨ iX i∈Top\vee_i X_i \in Top for their wedge sum and write ι i:X i→∨ iX i\iota_i \colon X_i \to \vee_i X_i for the canonical inclusion functions.
Proposition
For each n∈ℕn \in \mathbb{N} the homomorphism
(H˜ n(ι i)) i:⊕ iH˜ n(X i)→H˜ n(∨ iX i) (\tilde H_n(\iota_i))_i \colon \oplus_i \tilde H_n(X_i) \to \tilde H_n(\vee_i X_i)
is an isomorphism.
For instance (Hatcher, cor. 2.25).
Examples
For singular homology
For XX a topological space, write H n(X)H_n(X) for its singular homology with integer coefficients.
Example
The reduced singular homology of the 0-sphere S 0≃*∐*S^0 \simeq {*} \coprod {*} is
H˜ n(S 0)≃{ℤ ifn=0 0 otherwise. \tilde H_n(S^0) \simeq \left\{ \array{ \mathbb{Z} & if \; n = 0 \\ 0 & otherwise } \right. \,.
References
Reduced singular homology is discussed for instance around p. 119 of
Last revised on March 1, 2024 at 03:11:55. See the history of this page for a list of all contributions to it.